Question 1117822
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Use the Point-Slope form.  An equation of a line that has a slope *[tex \Large m] and contains the point *[tex \Large (x_1,\,y_1)] is 


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1)]


But put it in the form


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ mx\ -\ (mx_1\ +\ y_1)] 


Which, given that *[tex \Large m,\ x_1,\ ] and *[tex \Large y_1] are constants


reduces to 


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ mx\ +\ b]


Where the *[tex \Large y]-coordinate of the *[tex \Large y]-intercept is *[tex \Large b\ =\ -(mx_1\ +\ y_1)] 


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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