Question 1117749
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a) If the vertex angle of the cone is 90 degrees and the cone is filled to a depth of 24cm, then the radius of the surface of the water is 24cm.  Then the area of the surface of the water is {{{(pi)r^2 = 576pi}}}.<br>
b) The area of the water in contact with the cone is the lateral surface area of a cone: pi times the radius of the base times the slant height.<br>
{{{(pi)(r)(l) = (pi)(24)(24sqrt(2)) = 576pi*sqrt(2)}}}