Question 100681
[(x + 1)^3]^2 

=(x+1)^6 

= x^6 + 6C5x^5 + 6C4x^4 + 6C3x^3 + 6C2x^2 + 6C1x + 1

= x^6 + 6x^5 + 15x^4 + 20x^3 + 15x^2 + 6x + 1
=====================
Cheers,
Stan H.