Question 1117718
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1   1  -1    4
3  -1   1  -12
1  -4   2  -52

-3R1 + R2 -> R2

1   1  -1    4
0  -4   4  -24
1  -4   2  -52

-R1 + R3 -> R3
 
1   1  -1    4
0  -4   4  -24
0  -5   3  -56

-R2/4 -> R2

1   1  -1    4
0   1  -1    6
0  -5   3  -56

5R2 + R3 -> R3

1   1  -1    4
0   1  -1    6
0   0  -2  -26

-R3/2 -> R3

1   1  -1    4
0   1  -1    6
0   0   1   13

R3 + R1 -> R1
R3 + R2 -> R2

1   1   0   17
0   1   0   19
0   0   1   13

-R2 + R1 -> R1

1   0   0   -2
0   1   0   19
0   0   1   13

</pre>


The single element of the solution set is the ordered triple *[tex \Large \(-2,\,19,\,13\)]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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