Question 1117691
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Let *[tex \Large a] represent the number of coins in box A, *[tex \Large b] the number of coins in box B, and *[tex \Large c] the number of coins in box C.


We are given that:


1. *[tex \LARGE \ \ \ \ \ \ \ \ \ \ a\ =\ 5c]


2. *[tex \LARGE \ \ \ \ \ \ \ \ \ \ b\ =\ a\ -\ 12]


3. *[tex \LARGE \ \ \ \ \ \ \ \ \ \ c\ =\ \frac{b}{2}]


Substitute 2 into 3


4. *[tex \LARGE \ \ \ \ \ \ \ \ \ \ c\ =\ \frac{a\ -\ 12}{2}]


Substitute 1 into 4


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ c\ =\ \frac{5c\ -\ 12}{2}]


Solve for *[tex \Large c], then substitute *[tex \Large c] into 1 to solve for *[tex \Large a], then substitute *[tex \Large a] into 2 to solve for *[tex \Large b].


The amount of money in box A is *[tex \Large a] dollars.  The amount of money in box B is *[tex \Large \frac{b}{2}] dollars.  Find the difference between the two amounts.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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