Question 1117690
2.5^x=34.1^(2x+7)
x*log(2.5) = (2x+7)*log(34.1)
x*log(2.5) = 2x*log(34.1) + 7*log(34.1)
x*log(2.5) - 2x*log(34.1) = 7*log(34.1)
x*(log(2.5) - 2log(34.1)) = 7*log(34.1)
x = 7log(34.1)/(log(2.5) - 2log(34.1))
All the logs are just constants.
x =~ -2.55439411