Question 1117660
<font face="Times New Roman" size="+2">


It doesn't just say "*[tex \Large \frac{1}{7}] by 4", it says "greater than *[tex \Large \frac{1}{7}] by 4", which simply means *[tex \Large \frac{1}{7}\ +\ 4].


What number: *[tex \Large\ \ \  x]


*[tex \Large \frac{1}{5}] of which: *[tex \Large\ \ \  \frac{1}{5}x]


is:  *[tex \Large\ \ \  \frac{1}{5}x\ =]


greater than *[tex \Large \frac{1}{7}] by 4: *[tex \Large\ \ \  \frac{1}{5}x\ =\ \frac{1}{7}\ +\ 4]


Rewriting for ease of solving, noting that *[tex \Large\ \ \  4\ =\ \frac{28}{7}]:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x}{5}\ =\ \frac{29}{7}]


Just solve for *[tex \Large x].  Hint, don't waste your time trying to reduce the fractional answer.  5, 7, and 29 are all prime, so there will be no common factors in your final numerator and denominator.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

</font>