<PRE><B>Question 1117590</B>
There are 370 components produced by the three machines
:
a.i)  (6+120)/370 = 126/370
:
a.ii) 4/370
:
a.iii) 350/370 + 126/370 - 120/370 = 356/370
:
a.iv)  6/20
:
b) Machine I non-defective = 120/370, Machine II non-defective = 80/370, Machine III non-defective = 150/370, therefore Machine III has a higher probability of producing a non-defective part
:

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