Question 1117567
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To get an x^2 term, you need to take the "x" term 14 times and the "1/x^2" term 6 times:<br>
{{{(x^14)*(1/x^2)^6 = x^14/x^12 = x^2}}}<br>
So the x^2 term in the expansion is<br>
{{{C(20,6)*(x)^14*(-1/(2x^2))^6 = 38760x^14/64x^12 = (4845/8)x^2 = 605.625x^2}}}