Question 1117568
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To get a term independent of x, you need to take the "2x^3" term from 5 of the factors and the "1/(4x^5)" term from the other 3 factors.  So the term is<br>
{{{C(8,5)*(2x^3)^5*(1/(4x^5))^3}}}
{{{(56)*(32x^15)*(1/(64x^15))}}}
{{{56*32/64}}}
{{{28}}}<br>
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tutor ikleyn has pointed out that I lost track of a sign in the above response....<br>
The "1/4x^5" term in the binomial is negative, so the constant term is<br>
{{{C(8,5)*(2x^3)^5*(-1/(4x^5))^3}}}
{{{(56)*(32x^15)*(-1/(64x^15))}}}
{{{-56*32/64}}}
{{{-28}}}<br>