Question 1117543
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3, 5, 7, 9, and 11 are the possible odd results, then 6 and 12 are the even multiples of 3.  There are two ways to make 3, four ways to make 5, six ways to make 7, four ways to make 9, two ways to make 11, five ways to make 6, and one way to make 12.  There are 36 possible outcomes.


2 + 4 + 6 + 4 + 2 + 5 + 1 = 24.


So your desired probability is *[tex \Large \frac{2}{3}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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