Question 1117547
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You have written the height function incorrectly. *[tex \Large 16t^2] is the magnitude of the acceleration due to gravity, but acceleration due to gravity is in the direction of the center of the earth, so unless you are shooting the rocket straight down into the ground, the function that gives height in feet as a function of time in seconds is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ h(t)\ =\ -16t^2\ +\ v_0t\ +\ h_0]


Where *[tex \Large v_0] is the initial velocity of the projectile and *[tex \Large h_0] is the initial height of the projectile. 


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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