Question 1117499
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Equate the real and imaginary parts of the equation....<br>
{{{(x^4 + 2xi) - (3x^2 + yi) = (3 - 5i) + (1 +2yi)}}}<br>
{{{x^4-3x^2 = 4}}}; {{{2x-y = -5+2y}}}<br>
Solve the equation for the real parts to find the value(s) of x:<br>
{{{x^4-3x^2-4 = 0}}}
{{{(x^2-4)(x^2+1) = 0}}}<br>
There are 4 values for x: 2, -2, i, and -i.<br>
Solve the equation for the imaginary parts to find the corresponding values of y:<br>
{{{2x-y = -5+2y}}}<br>
{{{3y = 2x+5}}}<br>
{{{y = (2x+5)/3}}}<br>
4 solutions:
(1) x = 2; y = (4+5)/3 = 3
(2) x = -2' y = (-4+5)/3 = 1/3
(3) x = i; y = (2i+5)/3
(4) x = -i; y = (-2i+5)/3