Question 1117513
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On a sphere of a radius R, the spherical area of a triangle 


Spherical Area = {{{R^2*(A + B + C - pi)}}},


where A, B and C are spherical angles of the triangle in radians and the value  {{{A+B+C-pi}}}  is called  

"<U>the spherical excess of the triangle</U>"  (see the link  <A HREF=http://mathworld.wolfram.com/SphericalTriangle.html>http://mathworld.wolfram.com/SphericalTriangle.html</A> ).


So, from the given data,  {{{R^2}}} = {{{419/((pi/3))}}} = {{{(3*419)/3.14}}} = 400.3185.


Therefore, the radius of the sphere is about  {{{sqrt(400)}}} = 20 meters.
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