Question 1117475
 There are two numbers.When four times the larger number is added to three times the smaller number,the result is 26.If three times the larger number is decreased by twice the smaller number,the result is 11.Find the numbers.
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Equations:
4L+3S = 26
3L-2S = 11
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Modify for elimination:
12L + 9S = 3*26
12L - 8S = 4*11
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Subtract and solve for "S"::
Smaller = 34
Larger = (11+2*34)/3 = (11+68)/3 = 79/3 = 26 1/3
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Note:: The Larger turned out to be the Smaller.
You might want to check your posting.
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Cheers,
Stan H.
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Ch