Question 1117369
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Let *[tex \Large x] represent the price of 1 lb.  Then *[tex \Large \frac{3}{4}x] must be the price of *[tex \Large \frac{3}{4}] lb.  So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{3}{4}x\ =\ 3.75]


Solve for *[tex \Large x]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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