Question 1117323
{{{log((x))-1=-log((x-9))}}}

{{{log((x))+log((x-9))=1}}}

{{{log((x(x-9)))=1}}}  {{{using}}}{{{base}}}{{{ten}}}

{{{10^1=x(x-9)}}}

{{{x(x-9)=10}}}
The two factors could be 10 and 1.
{{{highlight(x=10)}}}