Question 1117287
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Half-angle formula:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sin\(\frac{\varphi}{2}\)\ =\ \sqrt{\frac{1\ -\ \cos{\varphi}}{2}}]


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sin\(\frac{A}{2}\)\ =\ \sqrt{\frac{1\ -\ \frac{1}{3}}{2}}]


You can do your own arithmetic.  My advice is to leave the answer in radical form AFTER you rationalize your denominator.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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