Question 1117297
 solve {{{e^(-4x)=9}}} 
using natural logs
{{{ln(e^(-4x)) = ln(9)}}}
the log equiv of exponent
{{{-4x*ln(e) = ln(9)}}}
the ln of e is 1, therefore
-4x = 2.197
x = {{{2.197/(-4)}}}
x = -.5493