<PRE><B>Question 1117250</B>
An airplane is flying 340 km/hr at 12 degrees East of North. The wind is blowing 40 km/hr at 34 degrees South of East. What is the plane’s actual velocity?
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1-hour coordinates::
x coordinate:: 340*cos(78 deg)+ 40cos(326 deg) = 103.85
y coordinate:: 340*sin(78 deg) + 40sin(326 deg) = 310.20
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distance in 1-hour
d = sqrt[103.85^2+310.20^2] = 327.12 km/hr
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Cheers,
Stan H.
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