Question 100591
{{{(25z^2-32)}}}=0 

{{{(25z^2-32+32)}}}=32
 {{{(sqrt(25z)^2)}}}= {{{(sqrt(32))}}}
 {{{(5z)}}}= {{{(4sqrt(2))}}} 
 {{{(5z/5)}}}= {{{(4sqrt(2)/5)}}}
 {{{(z)}}}= {{{(4sqrt(2)/5)}}}