Question 1117201
 if it is given that f(x)=x^2-5x-14,please help me to determine the value of k, for which f(x)=k will have two unequal positive real roots 
Solve::
x^2-5x-14 = k
x^2-5x-(14+k) = 0
----
Note:: b^2-4ac must be > 0
---------------------
25-4*1(-14-k) > 0
25+56+4k > 0
4k > -81
k > -81/4
-------
Cheers,
Stan H.
--------