Question 1115951
Let {{{u=4+x^(-2)}}}, then,
{{{du=-2x^(-3)dx}}}
So,
{{{int((4+x^(-2))(-2x^(-3)),dx)=int(u,du)}}}
{{{int((4+x^(-2))(-2x^(-3)),dx)=u^2/2+C}}}
{{{int((4+x^(-2))(-2x^(-3)),dx)=(1/2)(4+1/x^2)^2+C}}}