Question 1117179
Let s = length of each side of the square
The diameter  {{{d[1]}}} of the small circle is then {{{ s}}},  {{{ d[1] = s }}}
The diameter of the large circle is equal to the diagonal length of the square: {{{ d[2] = s*sqrt(2) }}}  


{{{ A[2] = pi*(d[2]/2)^2 = pi*(s^2*2)/4 }}}
{{{ A[1] = pi*(d[1]/2)^2 = pi*(s^2)/4) }}}

{{{ A[2]/ A[1] = highlight(  2  )}}}   —>  or equivalently, the ratio of large to small is  <b>2:1