Question 1116532
I'm assuming you mean the inverse(?).
Start with x,y definition,
{{{y=x/(x+1)}}}
Interchange x and y and solve for y.
This new y is the inverse of the original.
{{{x=y/(y+1)}}}
{{{x(y+1)=y}}}
{{{xy+x=y}}}
{{{xy-y=-x}}}
{{{y(x-1)=-x}}}
{{{y=-x/(x-1)}}}
{{{highlight(y[inv]=x/(1-x))}}}