Question 1116866
Need the mean of the data, and the 95% CI is mean +/- 1.96* 2/sqrt(n) when the population sd is known. (Otherwise it is s and the 1.96 is replaced with the appropriate t-value)
mean is 5.925
CI is 5.925+/- 1.96(2)/sqrt(20); the interval is 0.8765
(5.05, 6.80)