Question 1117033
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One possible combination is  (3 quarters, 4 dimes and 0 nickels).


The other possible combination is  (1 quarter, 9 dimes and 0 nickels).


And there are no other combinations
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It is a Math problem (a kind of entertainment problems).


It can be solved/proved formally by finding all possible combinations as the solutions of a Diophantine equation.


It can be solved logically by noticing that the necessary and sufficient condition for the solution is the absence of nickels in the combinations.