Question 1116981
it appears that what you are looking for is the equation of the line that has a slope of 2 that goes through the point (4,-6).


the slope intercept form of the equation of a line is y = mx + b


m is the slope and b is the y-intercept.


the slope is 2, therefore the equation becomes y = 2x + b.


to find b, replace x and y with the value of one of the points on the line and solve for b.


your equation becomes -6 = 2*4 + b


solve for b to get b = -6 - 8 = -14.


the y-intercept is the value of y when x is equal to 0.


that's the point where the line that is co-linear with (4,-6) meets the y-axis if the line has a gradient of 2 (gradient = slope).


your point is therefore (0,-14).


in my view, the other two equations are superfluous to the problem.


as it turns out, however, ths point (4,-6) is the intersection of the line formed by those equations.


the following graph shows you what i mean.


the line with the gradient of 2 is the green line.


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