Question 1116958
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{60!}{(50!)(10!)}]


You can do your own arithmetic, but if it takes 10 minutes to unfriend one combination of 50 friends out of 60, it would take you a little over 141,000 years to go through all of the combinations.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  


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