Question 1116863
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The solution by tutor ikleyn is fine.<br>
Here is a different path which leads to the same equation to solve and of course the same answer.<br>
Always be open to trying different methods for solving problems to find what methods "work" best for you.<br>
If the original number of sheep is n, then the cost for each one was 2100/n.<br>
Two of the sheep died, so the number he sold was (n-2).  <br>
He sold them for $30 more a head than he paid for them; so the selling price was (2100/n+30).<br>
Selling (n-2) sheep for that price made him a profit of $60, so he sold them for a total of $2160.<br>
So<br>
{{{(2100/n+30)(n-2) = 2160}}}
{{{2100-4200/n+30n-60 = 2160}}}
{{{30n-4200/n = 120}}}
{{{n-140/n=4}}}
{{{n-4-140/n=0}}}
{{{n^2-4n-140=0}}}
{{{(n-14)(n+10) = 0}}}
{{{n = 14}}}<br>
The number of sheep he bought was n=14.