Question 1116834
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Let *[tex \Large x] represent the number of nickels.  Let *[tex \Large y] represent the number of quarters.  Since there are 20 coins,


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  x\ +\ y\ =\ 20]


The number of cents in *[tex \Large x] nickels, since there are 5 cents in each nickel, is *[tex \Large 5x].  Similarly, the number of cents in *[tex \Large y] quarters is *[tex \Large 25y].


Since $4 is 400 cents, we can say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  5x\ +\ 25y\ =\ 400]


Solve the 2X2 system by any convenient means (I used the addition method, but substitution or Cramer's rule would work just as well).


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  


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