Question 1116763
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The area is one-half base times height; and we are given that the base b is 2 more than twice the height.  So
{{{(1/2)(b)(h) = 132}}}
{{{(1/2)(2h+2)(h) = 132}}}
{{{(h+1)(h) = 132}}}
{{{h^2+h = 132}}}
{{{h^2+h-132 = 0}}}<br>
That quadratic equation is solved rather easily, leading to the answers to the questions.