Question 1116531
.


&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;Calculation of (fog)(x) in the post by @josgarithmetic was &nbsp;&nbsp;<U>W R O N G</U>. 


&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;Below please find the correct calculation.



<pre>
(fog)(x) = 6*(x+3)^2 - 2*(x+3) - 1 = 6x^2 + 36x + 54 - 2x - 6 - 1 = 6x^2 + 34x + 47.
</pre>