Question 1116672
if you have this:

{{{f (x) = 8 -(1/7 )x}}}

then inverse is:

 {{{f (x) = y}}}

-> {{{y= 8 - (1/7 )x}}} ...swap {{{x}}} and {{{y}}}

 {{{x= 8 - (1/7 )y}}} ...solve for {{{y }}}

  {{{(1/7 )y = 8-x}}}

{{{y = 8/ (1/7 ) -x/ (1/7 )}}}

{{{y = 56 -7x}}}-> your inverse


{{{ graph( 600, 600, -10, 10, -10, 10,  8 -(1/7)x, 56-7x) }}}