Question 1116610


if given that the length {{{L}}} of a rectangle is six times its width {{{W}}}, we have 
{{{L=6W}}} ....eq.1

If the area of the rectangle is {{{A=150}}}, we have

{{{A=LW=150}}}

{{{LW=150}}}...substitute {{{L}}} with {{{6W}}}

{{{6W*W=150}}}

{{{W^2=150/6}}}

{{{W^2=25}}}

{{{W=sqrt(25)}}}

{{{W= 5}}}

and, {{{L=6W}}} =>{{{L=6*5}}} =>{{{L=30}}} 

then,

{{{P=2(L+W)}}}

{{{P=2(30+5)}}}

{{{P=2*35}}}

{{{P=70}}}