Question 1116546
Solve over the interval [0, 2pi) : 3cot^2x-3cotx-1=0
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*[invoke solve_quadratic_equation 3,-3,-1]
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tan(x) = 1/cot(x)
tan(x) = 0.79128786
x = 0.90139, 4.04298
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tan(x) = -3.791288
x = 4.9703, 1.82869