Question 100465
(X+5)(X+5)=289
X^2+10X+25=289
X^2+10X+25-289=0
X^2+10X-264=0
(X+22)(X-12)=0
X-12=0
X=12 FOR THE ORIGINAL SIZE OF THE PICTURE
PROOF
(12+5)(12+5)=289
17*17`=289
289=289