Question 1116554
------------------------------------------
...  Use the equation: Q(t)=q0e^-kt.
-------------------------------------------


{{{Q(t)=q[o]e^(-kt)}}}

-

If that is the way you want to make the model, then for the half-life information,


{{{1/2=e^(-kt)}}}
{{{ln(e^(-kt))=ln(1/2)}}}
{{{-kt=ln(1/2)}}}, and t=16;
{{{k=ln(1/2)/(-16)}}}
{{{k=ln(2)/16}}}
-
{{{k=0.04332}}} and more specific model equation is {{{Q(t)=q[o]e^(-0.04332t)}}}.


----------------------------------------------------------------------
When will 94% of the drug be removed from the body?
----------------------------------------------------------------------


That's same as 6% remaining in the body.

{{{100*e^(-0.04332*t)=6}}}

{{{e^(-0.04332t)=0.06}}}

{{{-0.04332t=ln(0.06)}}}

{{{t=ln(0.06)/(-0.04332)}}}

{{{highlight(t=65)}}},{{{hours}}}