Question 1116432
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Suppose P(A)=0.3 and P(B)=0.4 and P(A∩B)=0.12.  Find:


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a. P(B')                P(B') = 1 - P(B) = 1 - 0.4 = 0.6.


b. P((A&#8745;B)')            P((A&#8745;B)') = 1 - P(A&#8745;B) = 1 - 0.12 = 0.88.


c. P((A&#8746;B)')            First  P(A&#8746;B) = P(A) + P(B) - P((A&#8745;B) = 0.3 + 0.4 - 0.12 = 0.58

                        Then   P((A&#8746;B)') = 1 - P(A&#8746;B) = 1 - 0.58 = 0.42.


('=complement)
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