Question 1116432
Suppose P(A)=0.3 and P(B)=0.4 and P(A∩B)=0.12. Find:
a. P(B') = 0.6
b. P((A∩B)') = 0.88
c. P((A∪B)') 
P(A or B) = 0.18+0.12+0.28 = 0.58
So, P(A or B)' = 0.42
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Cheers,
Stan H.
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