Question 1116362
.
<U>A two-equations setup</U>


<pre>
5c +  3w = 23    (1)
2c + 12w = 47    (2)


Solve by Elimination. For it, multiply eq(1) by 4 (both sides). Keep eq(2) as is:


20c + 12w = 92   (1')
 2c + 12w = 47   (2')


Subtract eq(2') from  eq(1'). The terms "12w" will cancel each other, leaving you single equation for only one unknown "c".

It is how the Elimination method works.


20c - 2c = 92 - 47 = 45  ====>  c = {{{45/18}}} = 2.50.


Now from eq(2)  2*2.50 + 12w = 47  ====>  12w = 47 - 2*2.50 = 42  ====>  w = {{{42/12}}} = 3.50.


<U>Answer</U>.  cost for each pound of chocolate chips is $2.50  and of each pound of walnuts $3.50. 
</pre>

Solved.


On the way, &nbsp;you learned on how the Elimination method works.


=================


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The referred lessons are the part of this online textbook under the topic "<U>Systems of two linear equations in two unknowns</U>".



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