Question 1116305
A committee of 4 is to be chosen at random from among 5 women and 
6 men. What is the probability that the committee contains at least 
3 women?
<pre>
Case 1: 3 women and 1 man

Choose the 3 women 5C3 ways.
Choose the 1 man 6C1 ways.

That's (5C3)(6C1) = (10)(6) = 60 ways for case 1.

Case 2: 4 women and no men

Choose the 4 women 5C4 ways.

That's 5C4 = 5 ways for case 2.

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Answer: 60+5 = 65 ways.

Edwin</pre>