Question 100383
If I am reading the problem correctly, here is the answer;
{{{((-2)^3)^4*(-2)^6*(-2)^-5}}}
First multiply the power of 4 and the power of 3, a negative exponent turns integers into fractions;
{{{(-2)^12*(-2)^6*(1/-2^5)}}}
{{{(-2)^12*(-2)^6/(-2^5)}}}
since the bases are the same we can add the exponents;
{{{(-2)^18/(-2)^5}}}
You subtract exponents when the bases are the same and they are being divided, so we subtract 18-5;
{{{(-2)^13}}}
:)