Question 1115952
n=5                 x=2 
p=0.3
q=0.7
P(x) =   n!     * p^x *  q^(n-x)
      x! (n-x)!

P (x=2) = 5!   * 〖0.3〗^2 * 〖0.7〗^(5-2)
       2! (5-2)!

P (x=2) = 5 *4*3*2*1 * 〖0.3〗^2 * 〖0.7〗^3
          2*1(3)!
P (x=2) = 10 * 0.09 * 0.343
        
             = 0.3087