Question 1116140
{{{64+27w^3}}}

{{{(2^3)^2+3^3w^3}}}

{{{(2^2)^3+(3w)^3}}}

{{{4^3+(3w)^3}}}

A special factorization rule can be derived (or looked for in a reference source) for sum of cubes.


{{{(4+3w)(4^2-4*3w+(3w)^2)}}}


{{{(4+3w)(16-12w+9w^2)}}}