Question 1116114
 Nick tossed a penny off a 20 foot bridge.
 The path of the penny’s height can be modeled by the equation h(t) = -16t^2 + 40t + 20.
 Find the maximum height of the penny.
:
Find the axis of symmetry, x = -b/(2a); a=-16, b=40
t = {{{(-40)/(2*-16)}}}
t = {{{(-40)/(-32)}}}
t = 1.25 min to max height
:
h(t) = -16(1.25^2) + 40(1.25) + 20
h(t) = -16(1.5625) + 50 + 20
h(t) = -25 + 50 + 20
h(t) = 45 ft, max height