Question 1116083
What is the inverse function of: 
{{{f(x) = (1/2)^x}}}
y = f(x)
{{{y = (1/2)^x}}}
Swap x and y, solve for y
{{{x = (1/2)^y}}}
Find the y root of both sides
{{{x^(1/y) = 1/2}}}
Using common logs
{{{log((x^(1/y))) = log((1/2))}}}
the log equiv of exponents
{{{(1/y)log((x)) = log((1/2))}}}
multiply both sides by y
{{{log((x)) = y*log((1/2))}}}
divide both sides by log(1/2)
{{{log((x))/log((1/2))}}} = y
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