Question 1115972
Find the value of {{{(3a^2-ac+c^2)/(3b^2-bd+d2)}}} in terms of k. a/b=k;i.e a=bk, c/d=k, i.e c=dk.
In the numerator, replace a with bk, replace c with with dk
{{{3(bk)^2 - (bk)(dk) + (dk)^2}}}
{{{3b^2k^2 - bdk^2 + d^2k^2}}}
Factor out k^2
{{{k^2(3b^2 - bd + d^2)}}} 
with the denominator
 {{{k^2(3b^2 - bd + d^2)/(3b^2-bd+d^2)}}} 
fraction cancels, left with
{{{k^2}}}; k = 1