Question 1116024
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1.  44 + 33 + 44 = 121.



2.  The probability to get two red balls     = {{{(44*43)/(121*120)}}}.

    
    The probability to get two white balls   = {{{(33*32)/(121*120)}}}.


    The probability to get two green balls   = {{{(44*43)/(121*120)}}}.



3.  The probability to get two balls of the same color is  


     {{{(44*43)/(121*120) + (33*32)/(121*120) + (44*43)/(121*120)}}} = {{{(44*43+33*32+44*43)/(121*120)}}} = {{{(4*43+3*32+4*43)/(11*120)}}} = {{{440/(11*120)}}} = {{{40/120}}} = {{{1/3}}} = 0.3333 = 33.33%.
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