Question 1115677
if we have an x-intercept of {{{-2}}}, we have one point at ({{{-2}}},{{{0}}}) 

and 
a y-intercept of {{{1}}}, , we have one point at ({{{0}}},{{{1}}})

we need a slope:

{{{m=(y[2]-y[1])/(x[2]-x[1])}}} ...use points: 

({{{-2}}},{{{0}}}) and ({{{0}}},{{{1}}})


{{{m=(1-0)/(0-(-2))}}}

{{{m=1/(0+2)}}}

{{{m=1/2}}}

use slope point formula:

{{{y-y[1]=m(x-x[1])}}}.....plug in {{{m=1/2}}}  and coordinates of ({{{-2}}},{{{0}}})

{{{y-0= (1/2)(x-(-2))}}}

{{{y= (1/2)(x+2)}}}

{{{y= (1/2)x+1}}}-> your line